復制代碼代碼如下:[[email protected] ]#basename /root/aaa/bbb/dabu.txt
顯示：
復制代碼代碼如下:dabu.txt #獲取路徑的文件名
shell腳本中如何獲得腳本文件所在路徑？
方法一：
復制代碼代碼如下:[[email protected] ]#DIR=$(cd "$(dirname "$0")"; pwd)</p>
<p>[[email protected] ]#echo $DIR
但是像這種dirname "$0"這種寫法，在遇到source命令時會得到錯誤的結果。
方法二：
復制代碼代碼如下:[[email protected] ]#echo "$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd )"
上面一行命令可以獲得腳本的絕對輪徑，無論你在何處調用這個腳本。
但是如果含有軟鏈接，就無法使用了。所以，我們為了能正確解析指向腳本的軟鏈接，可以使用下面的多行命令：
復制代碼代碼如下: SOURCE="${BASH_SOURCE[0]}"
while [ -h "$SOURCE" ]; do # resolve $SOURCE until the file is no longer a symlink
DIR="$( cd -P "$( dirname "$SOURCE" )" && pwd )"
SOURCE="$(readlink "$SOURCE")"
[[ $SOURCE != /* ]] && SOURCE="$DIR/$SOURCE" # if $SOURCE was a relative symlink, we need to resolve it relative to the path where the symlink file was located
done
DIR="$( cd -P "$( dirname "$SOURCE" )" && pwd )"
也可與source,bash -c命令使用
但是，如果你在腳本中使用先cd切換到其他目錄，在運行時上面的命令片段時，則上面的命令不能等到正確的結果。可以參考關於$CDPATH 陷阱的文章。想理解它如何其作用的，可以運行下面的代碼：
復制代碼代碼如下: #!/bin/bash</p>
<p> SOURCE="${BASH_SOURCE[0]}"
while [ -h "$SOURCE" ]; do # resolve $SOURCE until the file is no longer a symlink
TARGET="$(readlink "$SOURCE")"
if [[ $SOURCE == /* ]]; then
echo "SOURCE '$SOURCE' is an absolute symlink to '$TARGET'"
SOURCE="$TARGET"
else
DIR="$( dirname "$SOURCE" )"
echo "SOURCE '$SOURCE' is a relative symlink to '$TARGET' (relative to '$DIR')"
SOURCE="$DIR/$TARGET" # if $SOURCE was a relative symlink, we need to resolve it relative to the path where the symlink file was located
fi
done
echo "SOURCE is '$SOURCE'"
RDIR="$( dirname "$SOURCE" )"
DIR="$( cd -P "$( dirname "$SOURCE" )" && pwd )"
if [ "$DIR" != "$RDIR" ]; then
echo "DIR '$RDIR' resolves to '$DIR'"
fi
echo "DIR is '$DIR'"